F(x)=8x^2+22x-21

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Solution for F(x)=8x^2+22x-21 equation:



(F)=8F^2+22F-21
We move all terms to the left:
(F)-(8F^2+22F-21)=0
We get rid of parentheses
-8F^2+F-22F+21=0
We add all the numbers together, and all the variables
-8F^2-21F+21=0
a = -8; b = -21; c = +21;
Δ = b2-4ac
Δ = -212-4·(-8)·21
Δ = 1113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{1113}}{2*-8}=\frac{21-\sqrt{1113}}{-16} $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{1113}}{2*-8}=\frac{21+\sqrt{1113}}{-16} $

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